(D) In Young's double slit experiment,the fringe width is given by $\beta = \frac{\lambda D}{d}$. Since the fringe width depends only on the wavelengt

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(D) In Young's double slit experiment,the fringe width is given by $\beta = \frac{\lambda D}{d}$. Since the fringe width depends only on the wavelength $\lambda$,the distance between slits $d$,and the distance to the screen $D$,the fringe width for dark and bright fringes is the same. Thus,the Assertion is incorrect.When white light is used as a source,the central fringe is white,and the subsequent fringes are coloured because different wavelengths have different fringe widths. Black fringes are not observed in the same way as monochromatic light. Thus,the Reason is also incorrect.

Class 12 Physics Wave Optics Young's Double Slit Experiment (YDSE)

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Assertion: In Young's experiment,the fringe width for dark fringes is different from that for bright fringes.
Reason: In Young's double slit experiment,if the fringes are performed with a source of white light,then only black and bright fringes are observed.

AIIMS 2001 All AIIMS

A
If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
B
If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
C
If the Assertion is correct but Reason is incorrect.
D
If both the Assertion and Reason are incorrect.

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Young's Double Slit Experiment (YDSE)

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In Young's double slit experiment,the slits are $0.5\, mm$ apart and interference pattern is observed on a screen placed at a distance of $1.0\, m$ from the plane containing the slits. If the wavelength of the incident light is $6000\ \mathring A$,then the separation between the third bright fringe and the central maxima is......$mm$.

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The path difference between two identical light waves at a point $Q$ on the screen is $3 \mu m$. If the wavelength of the waves is $5000 \text{ Å}$,then at point $Q$ there is:

MediumMHT CET 2023

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In a Young's double-slit experiment,the separation of the two slits is doubled. To keep the same spacing of fringes,the distance $D$ of the screen from the slits should be made

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Assertion: In Young's experiment,the fringe width for dark fringes is different from that for bright fringes.Reason: In Young's double slit experiment,if the fringes are performed with a source of white light,then only black and bright fringes are observed.

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In a Young's double slit experiment,the ratio of the amplitude of light coming from the slits is $2:1$. The ratio of the maximum to minimum intensity in the interference pattern is:

The path difference between two identical light waves at a point $Q$ on the screen is $3 \mu m$. If the wavelength of the waves is $5000 \text{ Å}$,then at point $Q$ there is:

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Assertion: In Young's experiment,the fringe width for dark fringes is different from that for bright fringes.
Reason: In Young's double slit experiment,if the fringes are performed with a source of white light,then only black and bright fringes are observed.